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Calculate the work done in increasing the radius of a soap bubble in air from 1 cm to 2 cm . The surface tension of soap solution is 30 dyne/cm . ( pi = 3.142 )
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The surface tension of a liquid is `10^(8)` dyne `cm^(-1)`. It is equivalent to - YouTube
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SOLVED:A soap bubble (surface tension 30 dyne/cm) has a radius of 2 cm. The work done in doubling its radius is (A) Zero (B) 2261 erg (C) 1135.5 erg (D) 9043 erg
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Calculate the work done in increasing the radius of a soap bubble in air from 1 cm to 2 cm. The surface tension of soap solution is 30 dyne/cm.(pi = 3.142)
A pressure of `10^(6)" dyne"//cm^(2)` is equivalent to : - YouTube
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A soap bubble having radius 1√(pi) cm is expanded to a bubble of radius 2√( pi) cm. If the surface tension of soap solution is 30 dynes/cm, the work done is:
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The surface tension of a liquid is 10^(8) dyne/cm .It is equivalent to
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