![The Bell System technical journal . are given by ,3 = 100 log22V (6) a = 10(log10£-logi0£]) (7) where E is the value of intensity corresponding to a pressure am-plitude of](https://c8.alamy.com/comp/2CNC5TP/the-bell-system-technical-journal-are-given-by-3-=-100-log22v-6-a-=-10log10-logi0-7-where-e-is-the-value-of-intensity-corresponding-to-a-pressure-am-plitude-of-1-dyne-substituting-values-of-3-a-0-1-log-10-a-10-ae-10-a-a0-450-the-number-of-tones-of-constant-intensity-which-are-perceivable-asdifferent-in-pitch-is-then-log-2-re-dp-1000-ltpj3-fa-a0-340320300280260240220i-200-80-60s40-5-120-100806040-10-number-of-pure-tonesperceptible-at-any-pitch-level-300-400-500-600-100-800-900-1000-1100-1100-1300-ho0-1500-1600-values-of-s8-16-32-64-128-2CNC5TP.jpg "The Bell System technical journal . are given by ,3 = 100 log22V (6) a = 10(log10£-logi0£]) (7) where E is the value of intensity corresponding to a pressure am-plitude of")
The Bell System technical journal . are given by ,3 = 100 log22V (6) a = 10(log10£-logi0£]) (7) where E is the value of intensity corresponding to a pressure am-plitude of
Newton (unit) - Wikipedia
Using dimensional analysis, show that 1N/m^2 = 10 dyne/cm^2
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The unit of force in SI system is newton (N) and in CGS system is dyne. One newton is equal to 1 kg m s^(-2) and 1 dyne is equal to 1
In SI system, the unit of P.E. is :
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SOLVED: 1 dyne is equal to
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1 newton = dynes.
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